Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-I
Rules 1,4,6,7,8
In this example, the permittee has taken an initial group of samples from ten randomly located line-point transects. The results of this sampling are as follows:
| transect no. (n) | acceptable points (out of 100) x | x2 |
| 1 | 86 | 7,396 |
| 2 | 90 | 8,100 |
| 3 | 76 | 5,776 |
| 4 | 82 | 6,724 |
| 5 | 40 | 1,600 |
| 6 | 76 | 5,776 |
| 7 | 40 | 1,600 |
| 8 | 82 | 6,724 |
| 9 | 86 | 7,396 |
| 10 | 90 | 8,100 |
now we need to calculate the variance, s2
number of transects (n) = 10
from the data in the above example, we calculate:
from the t table, we find t for a sample size of 10
n-1 = degrees of freedom
10-1 = 9 degrees of freedom for our example
from the t table, locate the t statistic for 9 degrees of freedom = 1.383
the sample adequacy formula is:
where:
0 = the sample mean
n = the number of samples which will need to be taken
t2 = t table value, squared
s2 = variance
plugging these values into the sample adequacy formula, we get:
Since we already have taken 10 samples and the sample adequacy formula tells us we need 13, we need to take an additional 3 transects (13 - 10 = 3).
When those 3 additional transects have been taken, a new variance must be calculated and the sample adequacy formula recalculated. This is to ascertain that the 3 additional transects didn't somehow increase the variance and, therefore, require still more transects. If this happens, the additional transects must be taken and the variance recalculated to determine sample adequacy.
The sample adequacy requirements must be fulfilled before a comparison to the standard can be made.
Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-I