Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-J
Rules 2, 4, 5
In this example, the permittee has taken an initial group of ten randomly located sampling frames. The results of the sampling are as follows:
| frame no. (n) | oven dry weight per sampling frame x | x2 |
| 1 | 72.2 | 5,212.84 |
| 2 | 80.0 | 6,400.00 |
| 3 | 22.0 | 484.00 |
| 4 | 96.5 | 9,312.25 |
| 5 | 100.2 | 10,040.04 |
| 6 | 25.0 | 625.00 |
| 7 | 81.0 | 6,561.00 |
| 8 | 96.0 | 9,216.00 |
| 9 | 100.9 | 10,180.81 |
| 10 | 51.0 | 2,601.00 |
| n=10 | [SIGMA]x = 724.8 | [SIGMA]x2 = 60,632.94 |
now we need to calculate the variance, s2
number of sampling frames (n) = 10
from the data in the above example, we calculate:
from the t table, we find t for a sample size of 10
n-1 = degrees of freedom
10-1 = 9 degrees of freedom for our example
from the t table, locate the t statistic for 9 degrees of freedom = 1.383
n = the number of samples which will need to be taken
t2 = t table value, squared (see Addendum G)
s2 = variance
plugging these values into the sample adequacy formula, we get:
Since we already have taken 10 samples and the sample adequacy formula tells us we need a total of 33, an additional 23 samples will need to be taken.
When the 23 additional samples have been taken, a new variance must be calculated and the sample adequacy formula recalculated. This is to ascertain that the additional samples didn't somehow increase the variance and, therefore, require still more samples. If this happens, the additional samples must be taken and the variance recalculated to determine sample adequacy.
Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-J