Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-H
Rules 1,7
This example assumes that eighty percent of the trees are more than three years old. If they are not, there is no reason to proceed with this analysis.
In performing statistical comparisons for tree and shrub stocking, results of randomly assigned sampling circles will be compared to the success standard, hypothetically 500 trees or shrubs/acre at a ninety percent confidence statistical interval, as illustrated in the following example:
Null hypothesis: Sample stocking rate on release area>= 450 trees and shrubs.
Alternate hypothesis: Sample stocking rate on release area< 450 trees and shrubs.
| release area sample results (x) | Target release stocking rate | |
| Assume that it | 10 | 450 trees and shrubs |
| took 10 samples | 9 | |
| to achieve sample | 5 | (90% of 500) |
| adequacy | 8 | = 9.0 trees/plot (1/50 acre sampling circle area) |
| 9 | ||
| 9 | ||
| 8 | ||
| 8 | ||
| 9 | ||
| 9 | ||
| [SIGMA]x = | 84 | |
If the sample stocking rate mean, 0, is >= the Target release stocking rate (9.0 in this example), then the sample stocking rate of the release area is greater than the Target release stocking rate and is successful. If, as in this example, the sample stocking rate mean, 0, is lower than the target release stocking rate, you must proceed with the t test as follows:
t table: 0.10 df (10-1) = 1.383. Since 1.4.5 >= 1.383, the null hypothesis is rejected. It can then be determined that the sample stocking rate of the release area is not greater than or equal to the target release stocking rate. The sample stocking rate fails.
Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-H