Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-M
Rules 7, 8
This example assumes that 80% of the trees are more than three years old. If they are not, there is no reason to proceed with this analysis.
In performing statistical comparisons for tree and shrub stocking, results of randomly assigned sampling circles will be compared to the success standard, 250 trees or shrubs/acre hypothetically in this example, at a ninety percent confidence statistical interval, as illustrated in the following example:
Null hypothesis: Sample stocking rate on release area >= the Target release stocking rate of trees and shrubs.
Alternate hypothesis: Sample stocking rate on release area < the Target release stocking rate of trees and shrubs.
| release area sample results (x) | Target release stocking rate | |
| assume that it | 4 | 225 trees and shrubs |
| took 10 samples (n) | 4 | (90% of 250) |
| to achieve sample | 4 | = 4.5 trees/plot (1/50 acre |
| adequacy | 4 | sampling circle area |
| 6 | ||
| 4 | ||
| 4 | ||
| 4 | ||
| 4 | ||
| 4 | ||
| [SIGMA]x = 42 sample stocking rate mean(0) = [SIGMA]x / n = 42/ 10 = 4.2 | ||
If the sample stocking rate mean, 0, is >= the Target release stocking rate, (4.5 in this example) then the sample stocking rate of the release area is greater than the Target release stocking rate and is successful. If, as in this example, the sample stocking rate mean, 0, is lower than the Target release stocking rate, you must proceed with the t test as follows:
Since 1.5 >= 1.383, the null hypothesis is rejected. It can be determined that the sample stocking rate of the release area is not greater than or equal to the Target stocking rate. The stocking rate fails
Miss. Code. tit. 11, pt. 8, ch. 2, app 11-8-2-A, 11-8-2-11-8-2-A-M